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Cn jji. The PDA has a nondeterministic branch at q1If the string is aibjck with i = j, then the PDA takes the branch from q1 to q2If the string is aibjck with j = k, then the PDA takes the branch from q1 to q5 We formally express the PDA as a 6tuple (Q,Σ,Γ,δ,q1,F), where Q = {q1,q2,,q8} Σ = {a,b,c}. The_Special_Advocate\ÿÇ›\ÿÇ›BOOKMOBIs9 % *¼ 2¤ ¼ B“ Iƒ Q² Y_ a hæ oM v` w\ y$ z qP `" ™D$ ™h& ™œ( >r* ^â ^ê0 Ò2 ˆ 4 Žø6 —÷8 ŸÊ §š ®ç> ¶ù@ ¿NB Ç8D νF ÖRH ÜäJ ä L épN érP êjR ì T ìvV íjX î‚Z ï‚\ ñ‚^ òþ` ó"b óFd ózf öh ö6j ÿ&l ØŽn دp Ø»r ¯G MOBI ý鹧»ô. (ii) d S ls fl ) d jax s f d l R;.
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Jan 25, 21 · Solution We can define the terms ‘s’ according to relation s i = s i1 i The value of ‘i’ increases by one for each iteration The value contained in ‘s’ at the i th iteration is the sum of the first ‘i’ positive integers If k is total number of iterations taken by the program, then while loop terminates if 1 2 3 k = k(k1)/2 > n So k = O(√n). The_Tragedy_of_King_Lear` ÜD` ÜEBOOKMOBI ;. I have a series of questions in which I need feedback and answers I will comment as to what I think, this is not a homework assignment but rather preparation for my exam My main problem is determining the iterations of a loop for different cases.
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